1.Dosage of reagent (PPM) = [(drop number /20) × dilution concentration/volume of test wastewater] ×106
★ PPM is one part per million, and the dosage is 1PPM, which is equivalent to 1 ton of wastewater, the dosage of the agent is 1 gram.
★ 1ML diluted solution is equivalent to 20 drops
2.Use a beaker to take 200ML of test wastewater (chroma 200, COD 110), adjust the PH value to 8, add 10 drops of decolorizing agent solution with an eyedropper (1ML is equivalent to 20 drops), stir, then add 12 drops of PAC, stir, and finally add 2 drops of PAM, stir, and stand for one minute. The detection chroma is 4(dilution multiple method) and COD is 85, which meets the national emission standard.
3. The dosage of the reagent preparation: decolorizing agent (2% solution, that is, dilution 50 times), PAC (2% solution), PAM(1‰ aqueous solution)
The amount of decolorizing agent = [(10/20) ×2%/200] ×106 = 50PPM
PAC dosage = [(12/20) ×2%/200] ×106 = 60PPM
The amount of PAM = [(2/20) ×1‰/200] ×106 = 0.5PPM
The amount of decolorizing agent is 50PPM, which is equivalent to 50 grams of the decolorizing agent stock solution in one ton of wastewater, and so on, PAC is 60 grams, and PAM is 0.5 grams.
Contact details:
Lanny.Zhang
Email : Lanny.zhang@lansenchem.com.cn
Whatsapp/wechat: 0086-18915315135
Post time: Mar-21-2025